F. None of the above [Cl^(-) is oxidized]
<em>No Cl atoms are available</em> to be oxidized, only Cl^(-)ions
2Cl^(-) → Cl_2 + 2e^(-)
The substance that <em>loses electrons</em> is oxidized.
Remember <em>OIL</em> RIG (<em>O</em>xidation<em> I</em>s <em>L</em>oss of electrons) and
<em>LEO</em> the lion says GER (<em>L</em>oss of Electrons is <em>O</em>xidation).
The atomic number is the number of protons in the nucleus of an atom. The number of protons define the identity of an element (i.e., an element with 6 protons is a carbon atom, no matter how many neutrons may be present).
Answer:
16 °C
Explanation:
Step 1: Given data
- Provided heat (Q): 811.68 J
- Mass of the metal (m): 95 g
- Specific heat capacity of the metal (c): 0.534 J/g.°C
Step 2: Calculate the temperature change (ΔT) experienced by the metal
We will use the following expression.
Q = c × m × ΔT
ΔT = Q/c × m
ΔT = 811.68 J/(0.534 J/g.°C) × 95 g = 16 °C