You would have to do the change in y over the change in x
1. 1-1/6-0
2. 0/6 and any time you divide zero by a number the answer is zero.
Answer:
x^4 -53x^2 +108x +160
Step-by-step explanation:
If <em>a</em> is a zero, then (<em>x-a</em>) is a factor. For the given zeros, the factors are ...
p(x) = (x +8)(x +1)(x -4)(x -5)
Multiplying these out gives the polynomial in standard form.
= (x^2 +9x +8)(x^2 -9x +20)
We note that these factors have a sum and difference with the same pair of values, x^2 and 9x. We can use the special form for the product of these to simplify our working out.
= (x^2 +9x)(x^2 -9x) +20(x^2 +9x) +8(x^2 -9x) +8(20)
= x^4 -81x^2 +20x^2 +180x +8x^2 -72x +160
p(x) = x^4 -53x^2 +108x +160
_____
The graph shows this polynomial has the required zeros.
Answer:
Step-by-step explanation:
5, -4
5-4=1
5(-4)=-20
Answer:
v= -1
Step-by-step explanation:
5+2v=3
2v=3-5
2v= -2
v= -2/2
v= -1
It would be no, because there is a lot of variability in the computer science book. Hope I help!