Answer:
Step-by-step explanation:
In the slope- intercept form (y= mx +c), the coefficient of x is the slope of the graph.
y= 3x +4
Slope of given line= 3
The product of the slopes of perpendicular lines is -1.
![(3)[ \frac{d - 4}{5 - ( - 2)} ] = - 1](https://tex.z-dn.net/?f=%20%283%29%5B%20%5Cfrac%7Bd%20-%204%7D%7B5%20-%20%28%20-%202%29%7D%20%5D%20%3D%20%20-%201)
Divide both sides by 3:
Cross multiply:
3(d -4)= -1(7)
Expand:
3d -12= -7
Add 12 on both sides:
3d= 12 -7
3d= 5
Divide both sides by 3:
Answer:
C. 10 ft.
Step-by-step explanation:
Area of 6 sq. ft. which is rectangular. The length is 3 ft and perimeter is l+l+w+w=perimeter. A rectangular shape has 2 sides of the same length and the other two are the same but, a different length the the other two sides.
Equation:
3+3+2+2=10
Answer:
B
Step-by-step explanation:
Trust
Answer: 32.14 after round off it will be 32
Step-by-step explanation:
This is how to round 32.14 to the nearest whole number. In other words, this is how to round 32.14 to the nearest integer.
32.14 has two parts. The integer part to the left of the decimal point and the fractional part to the right of the decimal point:
Integer Part: 32
Fractional Part: 14
Our goal is to round it so we only have an integer part using the following rules:
If the first digit in the fractional part of 32.14 is less than 5 then we simply remove the fractional part to get the answer.
If the first digit in the fractional part of 32.14 is 5 or above, then we add 1 to the integer part and remove the fractional part to get the answer.
The first digit in the fractional part is 1 and 1 is less than 5. Therefore, we simply remove the fractional part to get 32.14 rounded to the nearest whole number as:
32
We know that
At sea level, the height is 0 and
the pressure is 98 kilopascals
At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%
</span>i(100%-11.41%)/100----> (0.8859)
therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals
the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
