Please help! Correct answer only!

Mathematics

1 answer:

Tcecarenko [31]2 years ago

4 0

Answer:

" Expected Payoff " ⇒ $ 1.56 ; Type in 1.56

Step-by-step explanation:

Consider the steps below;

$Tickets That Can Be Entered - 1 Ticket,\\Total Tickets Entered - 1000 Tickets,\\\\Proportion - 1 / 1000,\\Money One ( First Ticket ) = 820 Dollars,\\Money One ( Second Ticket ) = 740 Dollars,\\\\Proportionality ( First ) - 1 / 1000 = x / 820,\\Proportionality ( Second ) - 1 / 1000 = x / 740\\\\1 / 1000 = x / 820,\\1000 * x = 820,\\x = 820 / 1000,\\x = 0.82,\\\\1 / 1000 = x / 740,\\1000 * x = 740,\\x = 740 / 1000,\\x = 0.74\\\\Conclusion ; " Expected Payoff " = 0.82 + 0.74 = 1.56$

Solution; " Expected Payoff " ⇒ $ 1.56

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Find three consecutive integers whose sum is 57????

Setler79 [48]

Answer:18 19 20

Step-by-step explanation:"Consecutive" means that the integers will follow each other in value, for example: 1, 2, 3 or 4, 5, 6. Also, no decimals are needed here because "integers" are whole, counting numbers. Here is the set up: Let x= the first integer Then X+1= 2nd consecutive integer and x+2= 3rd .

Suppose that x=1 x+1= 1+1=2 and x+2=1+2=3 However, you need specific consecutive numbers whose sum is 57. Remember that sum means to add:

x+ (x+1) + (x+2) = 57 Addition of all 3 consecutive numbers Now solve for x

and substitute into each part to come up with the three integers:

3x + 3= 57 3x=54 x=54/3 = 18 x=18, x+1= 18+1=19 x+2=18+2=20

Check your answer: 18+19+20=57 57=57 Check

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