Answer: The number of first-year residents she must survey to be 95% confident= 263
Step-by-step explanation:
When population standard deviation (
) is known and margin of error(E) is given, then the minimum sample size (n) is given by :-
, z* = Two-tailed critical value for the given confidence interval.
For 95% confidence level , z* = 1.96
As, = 8.265, E = 1
So, ![n= (\dfrac{1.96\times8.265}{1})^2 =(16.1994)^2\\\\= 262.42056036\approx263\ \ \ [\text{Rounded to the next integer}]](https://tex.z-dn.net/?f=n%3D%20%28%5Cdfrac%7B1.96%5Ctimes8.265%7D%7B1%7D%29%5E2%20%3D%2816.1994%29%5E2%5C%5C%5C%5C%3D%20262.42056036%5Capprox263%5C%20%5C%20%5C%20%5B%5Ctext%7BRounded%20to%20the%20next%20integer%7D%5D)
Hence, the number of first-year residents she must survey to be 95% confident= 263
So basically what you wanna do is multiply across giving you 40/88 which you can simplify down to 5/11
Hope this helps :D
Answer:
<h3>$825 it would be that</h3>
Step-by-step explanation:
<h3>it would be that all you have to do is multiple 55×15=825</h3><h3>5×5</h3><h3>
</h3>
Eight out of ten as a fraction = 8/10, as a decimal = 0.8
☆ 〜（ゝ。∂）
X = -4
As g(x) is replaced by g(-4)
plug in -4 for x inside the equation.
g(-4) = (-4) - 1g(-4) = -5
Plug in -4 for x in f(x)f(-4) = 4(-4) - 4f(-4) = -16 - 4f(-4) = -20
Now solve for f(x) over g(x)
remember, f(x) = -20, and g(x) = -5
-20/-5 = 4
4 should be your answer
hope this helpsClick to let others know, how helpful is it
