Complete Question
A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the drift velocity of the electrons. (The cross-sectional area of a 10-gauge wire is 5.261 mm2.)
mm/s
Answer:
The drift velocity is
Explanation:
From the question we are told that
The current on the copper is
The cross-sectional area is
The number of copper atom in the wire is mathematically evaluated
Where is the density of copper with a value
is the Avogadro's number with a value
Z is the molar mass of copper with a value
So
Given the 1 atom is equivalent to 1 free electron then the number of free electron is
The current through the wire is mathematically represented as
substituting values
=>
Answer:
Machine Efficiency
Explanation:
Efficiency is the percent of work put into a machine by the user (input work) that becomes work done by the machine (output work). The output work is always less than the input work because some of the input work is used to overcome friction. Therefore, efficiency is always less than 100 percent
Answer: because there is no displacement or movement in the watchman's work. according to science when displacement or movement take place it is said to be work. hope this helps you.
Answer:
W = 16.5 Kj
P = 49.9 Watt
E = 16471
Explanation:
m = 73.5kg
t = 5min 30sec = (5×60) + 30 = 330sec
each step = 16.6cm = 0.166m
h = 135×0.166 = 22.41 m
g = 10 m/s²
(i) W = F × s = W × h = mgh
W = 73.5×10×22.41 = 16471.35
W = 16.5 Kj
(ii) Power = workdone/time
P = 16471.35/330
P = 49.9 Watt
(iii) The energy burnt in this process = 16471