Which data set has a wider spread? Why? Set A: {9, 11, 24, 11, 4, 20, 16, 7, 18, 15, 28, 6} Set B: {9, 12, 15, 3, 21, 24, 5, 9,
olchik [2.2K]
Data Set A:
Lowest Value is 4
Highest Value is 28
Range = 28 - 4 = 24
Data Set B:
Lowest Value is 3
Highest Value is 24
Range = 24 - 3 = 21
Data Set A has bigger range than Data Set B, hence it has a wider range
Answer: Set A has a wider spread because its range is greater.
Answer:
a rectangle is a parallelogram as the parallogram is made up of 2 triangles and a smaller rectangle. When the rectangle is divided into 2 triangles and another small rectangle, and is then being put together with the triangles on each side, it will be a parallelogram.
Step-by-step explanation:
Answer:
<em>(12, 2)</em> is the original point on the graph of .
Step-by-step explanation:
<u>Given:</u>
has a point <em>(3, 6)</em> on its graph.
<u>To find:</u>
Original point on graph = ?.
<u>Solution:</u>
We are given that The point (3, 6) is on the graph of
If we put x = 3 and y = 6 in , it will satisfy the equation.
Let us the put the values and observe:
Now, let us compare the above with the following:
we get y = 2 and x = 12
So, the original point on graph of is <em>(12, 2).</em>
Answer:
2x-4+3x+2=48
5x-2=48
5x=48+2
5x=50
x=10
Step-by-step explanation:
this
Answer:
Both flights approach each other at a speed of 624.70 Knots. The FAA minimum separation is not violated as both airplanes are 7.26 Nautical miles away from each other at the time when one of the flights( flight AA) passes through Frada Heights.
Step-by-step explanation:
To solve this kind of problem, the knowledge of concept of relative velocity is needed as the first question requested how fast the flights were approaching each other. To find the minimum distance between both flights, the closest point of approach between both flights should be taken into consideration which was Frada heights. Flight AA passes through Frada Heights in a shorter time of 0.079 hours. This is the time at which both flights approach each other the closest and so the minimum distance (separation) between them. This was calculated to be 7.26NM which is greater than the FAA's minimum this requirement for flight was not violated.
Detailed calculation steps can be found in the attachment below.