Answer:The slope of the line is both ppsitive and linear.
Answer:
undefined slope
Step-by-step explanation:
There us change in rise but no change in run or x value. This means is a vertical line and it's slope is undefined.
Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
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Problem 2
<h3>Answer: True</h3>
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Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
(x-3)=-3x+25
Because we know that y=x-3 so we put that in place of y in the equation
The thickness of a brand new US penny that hasn't been
worn down is 1.52 millimeters.
If you have a million pennies, there are many ways to arrange them.
You can pile them all in one pile, or shovel them into many piles, or
stack them up in any number of stacks up to a half-million stacks
with two pennies in each stack, or try somehow to stack them all up
in one stack that's a million thicknesses high.
Any stack with 'n' pennies in the stack is 1.52n millimeters high.
If you somehow succeed in stacking all million of them in one stack,
then the height of that stack would be . . .
(1,000,000) x (1.52 mm) = 1,520,000 millimeters
152,000 centimeters
1,520 meters
1.52 kilometers
(about 59,842.5 inches
4,986.9 feet
1,662.3 yards
7.56 furlongs
0.944 mile
all rounded)
