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2 years ago

Can you guys pls give me the answer to this and why

Mathematics

1 answer:

NNADVOKAT [17]2 years ago

7 0

Answer:

x-3

Step-by-step explanation:

You can factor out a 3 from both terms of 3x^2 - 9x to get

3(x^2 - 3x)

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mixer [17]

Answer:

x = 20

Step-by-step explanation:

The angles shown are alternate exterior angles.

Alternate exterior angles are congruent

This means that 46 must equal 3x - 14

Note that we've just created an equation that we can use to solve for

We now use the equation to solve for x

3x - 14 = 46

add 14 to both sides

3x - 14 + 14 = 46 + 14

simplify

3x = 60

Divide both sides by 3

3x / 3 = x

60 / 3 = 20

We get that x = 20

4 0

2 years ago

13 Pts PLEASE SOMEONE HELP ME WITH THIS QUESTION PLZ EXPLAIN THANK U

AlexFokin [52]

It's the third one and the last one are the only ones that make immediate sense.

4 0

2 years ago

Read 2 more answers

Judy will use 2 1/2 cups of flour for each cake she bakes. Judy has 10 cups of flour. What is the maximum number of cakes Judy c

horsena [70]

Answer:

4 cakes

Step-by-step explanation:

3 0

2 years ago

4x^2-7x=15 Solve by factoring and please please please explain or show the work

vodomira [7]

Answer:

x=3 and x=-1.25

Step-by-step explanation:

4x^2-7x=15

subtract 15 from each side:

4x^2-7x-15=0

factor (trying different numbers that the sum is 7 and the quotient is 15)

(2x-6 )(2x+2.5 )=0

2x-6=0 add 6 to each side

2x=6

x=3

2x+2.5=0 subtract 2.5 from each side

2x=-2.5

x=-1.25

8 0

2 years ago

Suppose the lengths of two sides of a right triangle are represented by 2x and 3 (x + 1), and the longest side is 17 units. Find

densk [106]

Answer:

x=4

Step-by-step explanation:

Step 1:-

given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.

AB = 2x and BC = 3(x+1) and longest side AC= 17

by using Pythagoras theorem

$AC^2 = AB^2 + BC^2$

step 2:-

The hypotenuse is longest side is AC = 17 units

(17)^2 = 4x^2 +9(X+1)^2

on simplification, we will use formula

$(a + b)^2 = a^2 +2ab+b^2$

289 = 4x^2 +9(x^2+2x+1)

$13x^2 +18x-280 = 0$

finding factors 70 X 52 = 3640

$13x^2 +70x-52x-280 = 0$

$13x^2 -52x+ 70x-280 = 0$

Taking common , we get

13x(x-4)+70(x-4)=0

x-4=0 and 13x+70=0

x=4 and $13x =-70$

x=4 and $x=\frac{-70}{13}$

we can not choose negative value so x value is 4

Final answer:- x = 4

verification:-

$AC^2 = AB^2 + BC^2$

289 = 4(4)^2+9(4+1)^2

289 = 64 +9(25)

289=289

6 0

3 years ago

Read 2 more answers