Answer:
<u>Triangle ABC and triangle MNO</u> are congruent. A <u>Rotation</u> is a single rigid transformation that maps the two congruent triangles.
Step-by-step explanation:
ΔABC has vertices at A(12, 8), B(4,8), and C(4, 14).
- length of AB = √[(12-4)² + (8-8)²] = 8
- length of AC = √[(12-4)² + (8-14)²] = 10
- length of CB = √[(4-4)² + (8-14)²] = 6
ΔMNO has vertices at M(4, 16), N(4,8), and O(-2,8).
- length of MN = √[(4-4)² + (16-8)²] = 8
- length of MO = √[(4+2)² + (16-8)²] = 10
- length of NO = √[(4+2)² + (8-8)²] = 6
Therefore:
and ΔABC ≅ ΔMNO by SSS postulate.
In the picture attached, both triangles are shown. It can be seen that counterclockwise rotation of ΔABC around vertex B would map ΔABC into the ΔMNO.
Answer:
I think it B as well as the other person I just learned this so I'm not the best at it
Odd integers would include: -1, 1, and 3.
Answer:
1
Step-by-step explanation:
The quadratic function
y = -2(x + 2)² - 1
has no real zeros because its vertex is located at (-2, -1) and it opens downward (the leading coefficient, -2, is negative)
A quadratic function has one real root if its vertex has the form (x, 0). If we add 1 to our equation, we get:
y = -2(x + 2)² - 1 + 1 = -2(x + 2)²
which has point (-2, 0) as vertex
<span>Because he couldn't find a date</span>