Write -9.42 as a mixed number.

Here is a quote from an NPR news article: "On average, working-age adults were eating about 78 fewer calories per day in 2010, c

s2008m [1.1K]

Answer:

The answer is "Option d".

Step-by-step explanation:

It involves the use of quantitative templates, diagrams, or summaries in such a given set of experimental data or real-liability for research. This research method is used for gathering, analyzing, assessing, or making judgments.

The statistics are mostly a summary description and the entire nation is represented in a parameter.
It is 78 figure is a statistical figure based on a survey of 10,000 people, that's why choice d is correct.

8 0

2 years ago

Solve x2 – 10x + 25 = 35 for x.

Galina-37 [17]

$x^2-10x+25=35\\\\x^2-2\cdot5\cdot x + 5^2=35\ \ \ |\text{use:}\ (a-b)^2=a^2-2ab+b^2\\\\(x-5)^2=35\to x-5=\pm\sqrt{35}\ \ \ |+5\\\\\boxed{x=5-\sqrt{35}\ \vee\ x=5+\sqrt{35}}$

$\text{other method}\\\\x^2-10x+25=35\\\\x^2-5x-5x+25=35\\\\x(x-5)-5(x-5)=35\\\\(x-5)(x-5)=35\\\\(x-5)^2=35\\.....$

3 0

3 years ago

(**15 POINTS**)

bonufazy [111]

Answer:

0.6x = 87

Step-by-step explanation:

Hi, to answer this question we have to write en equation:

We have to multiply the variable x by the percentage given (60%) in decimal form (divided by 100). That expression must be equal to 87.

Mathematically speaking:

x (60/100) = 87

0.6x = 87

Feel free to ask for more if needed or if you did not understand something.

8 0

2 years ago

A family now pays rent of $540 per month. If they buy a house, their housing expense will be $825 per month. How much more will

pishuonlain [190]

825 - 540 = 285
They will pay $285 more per month

7 0

2 years ago

Read 2 more answers

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species

kotegsom [21]

Answer:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

Step-by-step explanation:

The logistic equation is the following one:

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that $P(0) = 80, K = 2000$ .