4. – 2y = -510.x + 20y = -2

Mathematics

1 answer:

kari74 [83]2 years ago

4 0

Answer:

10 • (x - 2y + 3z)

? if thats the answer.

and y = 5/2 = 2.500 for the - 2y = -5 one. if they are both combined please comment under mine.

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4x+6 find find the value

Alex Ar [27]

Answer:

-1.5 or -6/4

Step-by-step explanation:

Im assuming the equation is 4x+6=0

1.) subtract the 6 from each side.

4x= -6

2.) you need to isolate the X, so divide the 4 from each side.

X= -6/4 or -1.5

7 0

2 years ago

Find the length of the unknown side. Round your answer to the nearest tenth.

Paraphin [41]

Answer:

The correct option is: 11.5

Step-by-step explanation:

Suppose, the length of the unknown side is $x$

So, here the length of hypotenuse is 14 and the lengths of other two sides are 8 and $x$ .

As the given triangle is right angle triangle, so using Pythagorean theorem, we will get.........

$8^2+x^2= 14^2\\ \\ 64+x^2=196\\ \\ x^2=196-64=132\\ \\ x=\sqrt{132}=11.489...\approx 11.5$

(Rounded to the nearest tenth)

So, the length of the unknown side is 11.5

6 0

2 years ago

Read 2 more answers

9, 2.5, –4, –10.5, –17, .

Vedmedyk [2.9K]

What do you mean? If you want it in order than you can say it. -17, -10.5, -4, 2.5, 9

7 0

3 years ago

PLEASE HELP ILL GIVE BRAINLIEST

dusya [7]

$(-2+\sqrt{-5})^2\implies (-2+\sqrt{-1\cdot 5})^2\implies (-2+\sqrt{-1}\sqrt{5})^2\implies (-2+i\sqrt{5})^2 \\\\\\ (-2+i\sqrt{5})(-2+i\sqrt{5})\implies +4-2i\sqrt{5}-2i\sqrt{5}+(i\sqrt{5})^2 \\\\\\ 4-4i\sqrt{5}+[i^2(\sqrt{5})^2]\implies 4-4i\sqrt{5}+[-1\cdot 5] \\\\\\ 4-4i\sqrt{5}-5\implies -1-4i\sqrt{5}$

let's recall that the conjugate of any pair a + b is simply the same pair with a different sign, namely a - b and the reverse is also true, let's also recall that i² = -1.

$\cfrac{6-7i}{1-2i}\implies \stackrel{\textit{multiplying both sides by the denominator's conjugate}}{\cfrac{6-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(6-7i)(1+2i)}{\underset{\textit{difference of squares}}{(1-2i)(1+2i)}}} \\\\\\ \cfrac{(6-7i)(1+2i)}{1^2-(2i)^2}\implies \cfrac{6-12i-7i-14i^2}{1-(2^2i^2)}\implies \cfrac{6-19i-14(-1)}{1-[4(-1)]} \\\\\\ \cfrac{6-19i+14}{1-(-4)}\implies \cfrac{20-19i}{1+4}\implies \cfrac{20-19i}{5}\implies \cfrac{20}{5}-\cfrac{19i}{5}\implies 4-\cfrac{19i}{5}$