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2 years ago

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What two equivalent ratios for 30 to 6

1 answer:

alexgriva [62]2 years ago

5 0

Two equivalent ratios for 30 to 6 can be 15 to 3 or 45 to 9

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Danny buys 4 pizzas and some pretzels for his baseball team. The cost of each pizza is $8.99, and the cost of each pretzel is $0

Luba_88 [7]

Answer:

Step-by-step explanation: The answer to your question is 15 pretzels.To figure this out, you first multiply 8.99 by 4 since he did buy 4 pizzas and each pizza is 8.99. Then once you do that, you should come up with 35.96. Then subtract 50.81 from 35.96,which should give you 14.85. Then just divide 14.85 by 0.99 to figure out the amount of pretzels he bought.It should give you 15.Hope this helps!!!!

Please give brainliest!!!☺

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2 years ago

Read 2 more answers

A swimming pool had

Alinara [238K]

I believe your answer is 75 percent but i’m not 100 percent sure

8 0

2 years ago

What is true about the completely simplified sum of the polynomials 3x squared y squared minus 2 x y to the power of 5 and negat

12345 [234]

Answer:

The sum is a binomial with a degree of 6.

Step-by-step explanation:

To find : What is true about the completely simplified sum of the polynomials $3x^2y^2-2xy^5$ and $-3x^2y^2+3x^4y$ ?

Solution :

The polynomials $3x^2y^2-2xy^5$ and $-3x^2y^2+3x^4y$ ,

The sum of polynomial is given by,

$S=3x^2y^2-2xy^5+(-3x^2y^2+3x^4y)$

On simplifying , we get,

$S=3x^2y^2-2xy^5-3x^2y^2+3x^4y$

$S=-2xy^5+3x^4y$

Therefore, the result obtained is a binomial with a degree of 6.

4 0

2 years ago

A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl

Andrew [12]

Answer: $\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$ or $\dfrac{228}{91885}$ .

Step-by-step explanation:

Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.

The total number of cards in a deck 52

Number of faces cards in a deck = 12

Number of cards not face cards = 40

The total number of combinations of drawing 9 cards out of 52 cards = $^{52}C_9$

Now , the combination of 9 cards such that exactly 6 of them are face cards = $^{12}C_{6}\times^{40}C_3$

Now , the probability that the hand contains exactly 6 face cards will be :-

$\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$

$=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}$

Hence, the probability that the hand contains exactly 6 face cards. is $\dfrac{228}{91885}$ .

6 0

2 years ago

Find the slope of the line that passes through the following points. (-2, 8) and (3, -2)

Elodia [21]

Answer:

m=-2

Step-by-step explanation:

m=y2-y1/x2-x1

m=-2-8/3-(-2)

m=-2-8/3+2

m=-10/5

m=-2

3 0

1 year ago