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3 years ago

Help please 10 points

Mathematics

1 answer:

-BARSIC- [3]3 years ago

6 0

the answer is A

im doing this too ;P

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Pls help me...how do u factor that ?

Leya [2.2K]

Answer:

(2x - 1)(2x + 1)(x - 7)

Step-by-step explanation:

We use grouping to factor.

Step 1: Group 1st 2 terms together and factor

4x³ - 28x²

4x²(x - 7)

Step 2: Group last 2 terms together and factor

-x + 7

-1(x - 7)

Step 3: Combine

(4x² - 1)(x - 7)

Step 4: Factor out quadratic

(2x - 1)(2x + 1)(x - 7)

4 0

2 years ago

Find the value of x in the following figure. Show equations and work that lead to your answer.

UkoKoshka [18]

Answer:

x=7

Step-by-step explanation:

We have been given all exterior angles of a quadrilateral which is a polynomial having 4 sides

We know that sum of all exterior angles of a regular polygon is always 360 degree.

So we can all given exterior angles and set it equal to 360

(12x+37)+(12x-2)+(46)+(20x-29)=360

12x+37+12x-2+46+20x-29=360

12x+12x+20x+37-2+46-29=360

44x+52=360

44x=360-52

44x=308

divide both sides by 44

x=7

Hence final answer is x=7.

4 0

2 years ago

I need to go 1,373 miles but the plane travels at 575 miles per hour. how long would it take me to get to my destination?

-BARSIC- [3]

Answer:2.38782608695652173913043478260869565217

Step-by-step explanation:

you divide 1373 by 575

4 0

2 years ago

Root 3 cosec140° - sec140°=4 prove that

Lorico [155]

Answer:

Step-by-step explanation:

We are to show that $\sqrt{3} cosec140^{0} - sec140^{0} = 4\\$

Proof:

From trigonometry identity;

$cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}$

$\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\$

From trigonometry, 2sinAcosA = Sin2A

$= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\= \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2 \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}$