To solve this problem, we need to know that
arc length = r θ where θ is the central angle in radians.
We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, θ
Rearrange equation at the beginning,
θ = (arc length) / r = 4pi / 6 = 2pi /3
Answer: the central angle is 2pi/3 radians, or (2pi/3)*(180/pi) degrees = 120 degrees
Answer:
E-F and E-D
C-B and C-D
Step-by-step explanation:
The circle and triangle are as shown. The options are:
- A-B and C-B
- E-F and E-D
- E-D and C-D
- A-F and E-F
- C-B and C-D
By drawing radius lines from the center of the circle to the tangent points B, D, and F, we can divide the triangle into 3 kites. Therefore, only segments that are legs of the same kite are congruent. So the answer must be E-F and E-D, and C-B and C-D.
Answer:
keep trying until you succeed :)
Step-by-step explanation:
Answer:
b.
Step-by-step explanation:
Seats to minutes = 2 to 11:
2/11 = s/m.
When s = 16:
2/11 = 16/m
m = 11*16 / 2
= 176/2
= 88 minutes.
When s = 19:
2/11 = 19 / m
m = 11*19 / 2
m = 209/2
= 104.5 minutes.
Answer:
Neither
Step-by-step explanation:
To tell if lines are perpendicular or parallel just from the equations, you need to look at the slopes. So get the equations into slop-intercept form
(y = slope * x + y-intercept)
2x = 14 + y
-14 -14
2x - 14 = y OR y = 2x - 14
*So the slope of the first equation is 2*
4x + 2y = 10
-4x -4x
2y = -4x + 10
/2 /2
y = -4/2 + 10
*So the slope is -2*
For the lines to be parallel, the slopes have to be the same. For them to be perpendicular, the slopes have to be opposite (negative is the opposite of positive and vice versa) and reciprocal (A flipped fraction, so the reciprocal of 2 would be 1/2)
