Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
Answer:
17 lb I guess 8 don't think the question is full
Step-by-step explanation:
the question is half
(16/18)
(24/27)
You just times 8 and 9 by the same number, like:
(8•2/9•2)=(16/18)
(8•3/9•3)=(24/27)
You could do any number:
(8•100/9•100)=(800/900)
6.23+ -12.49 -2.6= 6.23+ -12.49+ -2.6
-6.26+-2.6= -8.86
