Answer:
exact value:
approximate: x=0.349485
Step-by-step explanation:
Exact Value:
Approximate:
Answer:
The probability that the aircraft is overload = 0.9999
Yes , The pilot has to be take strict action .
Step-by-step explanation:
P.S - The exact question is -
Given - Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.
To find - What is the probability that the aircraft is overloaded ?
Should the pilot take any action to correct for an overloaded aircraft ?
Proof -
Given that,
Mean, μ = 182.7
Standard Deviation, σ = 39.6
Now,
Let X be the Weight of the men
Now,
Probability that the aircraft is loaded be
P(X > 168 ) = P( )
= P( z > )
= P( z > -0.371)
= 1 - P ( z ≤ -0.371 )
= 1 - P( z > 0.371)
= 1 - 0.00010363
= 0.9999
⇒P(X > 168) = 0.9999
As the probability of weight overload = 0.9999
So, The pilot has to be take strict action .
Step-by-step explanation:
simplify the expression into like terms
so 5a-2b-3+2b-6a (add all a and b together)
this will make
-a-3
I know how to do the equivalent sorry :(
Answer: 1:52 PM
Step-by-step explanation:
PAULA: 2:14PM FINISHED THE RACE
BEATRICE: FINISHED 22 MINUTES EARLIER THEN PAULA
YOU TAKE 2:14PM AND SUBTRACT THE 22 MINS BEATRICE RAN TO GET YOU ANSWER.
SO 2:14 -14 MINS=2:00PM 14+8=22 (THE MINS BETRICE FINISHED)
2:00-8 MINS ( REMAINING FROM THE 22 ) THEN 2:00-8 MINS =1:52
ANSWER:1:52PM