Answer:
b. Mg (s) + 2HCl (aq) --> MgCl2 (aq) + H2
Explanation:
A subscript applies only to the element it is attached to while coefficients apply to all elements in a compound.
"a" has 1 atom of each element on the left but 2 Cl on the right.
"c" has 2 Mg, 1 H, & 1 Cl on the left but 1 Mg, 2 H, and 2 Cl on the right.
"d" has 2 atoms of each element on the left but only 1 Mg on the right.
"b" is the only answer with equal numbers of atoms on the right and left sides of the equation.
A typical example of metal ore is copper which is used for production of electrical wires.
<h3>What are metal ores?</h3>
Metal ores are defined as the metals that are naturally deposited at the earth crust which can serve as a valuable resources for many industries.
The copper is a typical example of a metal ore which is a good conductor of electricity used for production of electrical wires.
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The name of the three compounds are Disulfur Dichloride, Potassium nitrate and Ammonium bromide respectively.
<h3>
What are the names of the given compounds?</h3>
1. The name of the first compound is <u>Disulfur Dichloride</u><u>.</u>
Disulfur Dichloride is a type of inorganic compound comprise of sulfur and chlorine. There are also many other names which we can be used like sulfur monochloride, disulphur dichloride and sulphur monochloride. It is used to show C-S bonds.
2. The name of the second compound is <u>Potassium nitrate.</u>
Potassium nitrate is a compound that belong to the alkali metal nitrate. Potassium nitrate is also known as Indian saltpetre. The potassium nitrate is present in the nature but in the form of mineral. The potassium nitrate is used for making the explosives, matches, rocket fuel and fireworks.
3.The name of the third compound is <u>Ammonium bromide.</u>
Ammonium bromide is a type of compound that contains ammonium salt of hydrobromic acid. It can melt easy on providing heat. It is also soluble in water. It gives yellow colour. Ammonium bromide is the weak acid.
So we can conclude that the name of the three compounds are Disulfur Dichloride, Potassium nitrate and Ammonium bromide respectively.
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The balanced equation for combustion is as follows;
2CH₃OH + 3O₂ ---> 2CO₂ + 4H₂O
The stoichiometry of CH₃OH to O₂ is 2:3
the limiting reagent is the reactant that is fully consumed during the reaction. The amount of product formed is directly proportional to the amount of limiting reactant produced. The excess reagent is the reactant that is provided in excess and is not fully used up, there will be an amount of this reagent remaining after the reaction.
If methanol is the limiting reactant,
If 2 mol of methanol reacts with 3 moles of O₂
Then 24 mol of methanol reacts with - 3/2 x 24 = 36 mol of O₂ should be present
But only 15 mol of O₂ is present, therefore O₂ is the limiting reactant and methanol is in excess.
3 mol of O₂ reacts with 2 mol of CH₃OH
then 15 mol of O₂ reacts with 2/3 x 15 = 10 mol of CH₃OH
Excess reactant is methanol, 10 mol are used up therefore 24 - 10 mol = 14 mol are remaining at the end of the reaction