All categories

2 years ago

How many amps of current are there in a system with 12 volts and 6 ohms?

Physics

2 answers:

Gemiola [76]2 years ago

7 0

V = IR
I = V/R
I = 12/6
I = 2 amps

soldi70 [24.7K]2 years ago

4 0

B.) According to Ohms law, I = V/R = 12/6 = 2amps.

You might be interested in

WILL MARK BRAINLIEST<br> If it takes you 70s to run the track, what is your velocity?

tiny-mole [99]

Answer:

Explanation:

But you have to be fat though lol

5 0

2 years ago

What is the difference between muscular strength and muscular endurance

MAXImum [283]

Muscular strength is a measure of how much force you can exert in one repetition. Muscular endurance refers to the ability to perform a specific muscular action for a prolonged period of time.

4 0

2 years ago

Read 2 more answers

a child hits a ball with a force of 350 N. (a) If the ball and bat are in contact for 0.12 is, what impulse does the ball receiv

Lina20 [59]

Explanation:

Given that,

Force with which a child hits a ball is 350 N

Time of contact is 0.12 s

We need to find the impulse received by the ball. The impulse delivered is given by :

$J=F\times t\\\\J=350\times 0.12\\\\J=42\ N-m$

So, the impulse is 42 N-m..

We know that he change in momentum is also equal to the impulse delivered.

So, impulse = 42 N-m and change in momentum =42 N-m.

7 0

2 years ago

Manmade global warming is caused by what?

kirill [66]

Human activities is the main reason of global warming such as factories and cars that causes carbon dioxide , carbon monoxide and other toxic gases

4 0

2 years ago

An ice skater of mass m = 60 kg coasts at a speed of v = 0.8 m/s past a pole. At the distance of closest approach, her center of

IrinaVladis [17]

Answer:

1.78 rad/s

1.70344 rad/s

Explanation:

v = Velocity = 0.8 m/s

m = Mass of person = 60 kg

$r_1$ = Distance between center of mass of person and pole = 0.45 m

$r_2$ = New distance between center of mass of person and pole = 0.46 m

I = Moment of inertia

Angular speed is given by

$\omega_1=\dfrac{v}{r_1}\\\Rightarrow \omega_1=\dfrac{0.8}{0.45}\\\Rightarrow \omega_1=1.78\ rad/s$

The angular speed is 1.78 rad/s

In this system the angular momentum is conserved

$L_1=L_2\\\Rightarrow I_1\omega_1=I_2\omega_2\\\Rightarrow mr_1^2\omega_1=mr_2^2\omega_2\\\Rightarrow \omega_2=\dfrac{r_1^2\omega_1}{r_2^2}\\\Rightarrow \omega_2=\dfrac{0.45^2\times 1.78}{0.46^2}\\\Rightarrow \omega_2=1.70344\ rad/s$

The new angular speed is 1.70344 rad/s

7 0

2 years ago