A ball falling though the air has ?
1 answer:
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Answer:
10604 square meters
Explanation:
0.23 cm = 0.0023m
Assume the carrier has a shape of a rectangular box. When the carrier sinks 0.0023m deeper into water, the extra volume submerged into water is the same as the extra water volume being replaced. This extra volume would add an additional buoyant force to counter balance the extra weight created by the 25000 kg fighter.
With g being constant, the mass of the extra water displaced is the same as the mass of the fighter airplane . And mass of the water displaced is its volume V times its density
We assume the carrier has a shape of a rectangular box, so this extra displaced volume is the extra depth d = 0.0023 m times cross-section area A
The correct answer to the question is : B) 132 Joules.
EXPLANATION :
As per the question, the mass of the gold m = 3 gram.
The initial temperature of the gold T = 21 degree celsius.
The final temperature of the gold T' = 363 degree celsius.
Hence, the change in temperature dT = T' - T
= 363 - 21 degree celsius
= 342 degree celsius.
The specific heat of the gold is given as c =
We are asked to calculate the heat required ( dQ ) to raise the temperature of gold.
The heat required for this is calculated as -
dQ = mcDT
= 3 × 342 × 0.129 J
= 132.354 J
≈ 132 J
Hence, the correct answer is 132 J.