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Answer:
The quantity of coffee costing $4 a pound in the coffee mixture is 2 pounds.
Step-by-step explanation:
Given: Coffee costing $4 a pound is mixed with 3 pounds of coffee costing 4.50 a pound to obtain a mixture costing $4.30 a pound.
We have to find the quantity of coffee costing $4 a pound in the mixture.
Let x represent the number of pounds of $4 coffee.
Cost of one pound = 4x.
Cost of 3 pounds of coffee costing 4.50 a pound = 3(4.50)
Cost of mixture costing $4.30 a pound = (x+3)(4.30)
According to given problem,
Solving for x, we get,
Rearranging like term together, we get,
Thus, the quantity of coffee costing $4 a pound in the coffee mixture is 2 pounds.
Now, recall that I = Prt.
now, half of the original principal is just P/2, so, how many years will it take Jim to get in interest, an amount that is half of what he put in.
now.... neverminding P amount, we can say... that say if P = 2, then I = 1, because we want I to be half of P, and when that happens, every $2 returned $1 in interest with a 10% simple interest, what year is it?
now, half of the original principal is just P/2, so, how many years will it take Jim to get in interest, an amount that is half of what he put in.
now.... neverminding P amount, we can say... that say if P = 2, then I = 1, because we want I to be half of P, and when that happens, every $2 returned $1 in interest with a 10% simple interest, what year is it?