The subtraction of complex numbers is cos(π)+i sin(π).
Given [cos(3π/4+i sin(3π/4) and =cos (π/2) +i sin(π/2)
We have to find the value of .
A complex number is a number that includes real number as well as a imaginary unit in which . It looks like a+ bi.
We have to first solve and then we will be able to find the difference.
[ cos (3π/4)+i sin (3π/4)]
[cos(π-π/4)+ i sin (π-π/4)]
= [-cos(π/4)+sin (π/4)]
=(-1/+1/)
=
=0
cos(π/2)+i sin (π/2)
=0+i*1
=1
Now putting the values of ,
=-1
=-1+i*0
=cos (π)+i sin(π)
Hence the value of difference between is cos(π)+i sin(π).
Learn more about complex numbers at brainly.com/question/10662770
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Hey there!!
Given equation :
... -4 ( x + 10 ) - 6 = -3 ( x - 2 )
Using the distributive property :
... -4x - 40 - 6 = -3x + 6
Combining like terms :
... -4x - 46 = -3x + 6
Adding 46 on both sides :
... -4x = -3x + 52
Adding 3x on both sides :
... -x = 52
... x = -52
Hope helps!
Answer:
-63q-54
Step-by-step explanation:
When using the distributive property, you multiply everything inside of the parentheses by the number outside of the parentheses.
9(-7q-6)
-63q-54
Hope this helps, and have a great day o(* ̄▽ ̄*)ブ