Answer:
If all you care about is whether you roll 2 or not, you get a Binomial distribution with an individual success probability 1/6. The probability of rolling 2 at least two times, is the same as the probability of not rolling 2 at zero or one time.
the answer is, 1 - bin(k=0, n=4, r=1/6) - bin(k=1, n=4, r=1/6). This evaluates to about 13%, just like your result (you just computed all three outcomes satisfying the proposition rather than the two that didn’t).
Step-by-step explanation:
1.54 + 2.37
= (1 + 5/10 + 4/100) + (2 + 3/10 + 7/100)
= 1 + 5/10 + 4/100 + 2 + 3/10 + 7/100
= 3 + 8/10 + 11/100
= 3 + 8/10 + (10/100 + 1/100)
= 3 + 8/10 + (1/10 + 1/100)
= 3 + 8/10 + 1/10 + 1/100
= 3 + 9/10 + 1/100
= 3.91
7.
15/2= 7.5
you cant get 7 and a half action figures so round down to 7
Hope this helps
You have to rearrange the formula
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