Given that the hypotenuse of the isosceles right triangle
=
14
,
⇒
the length of each leg
=
14
√
2
=
7
√
2
Check :
(
7
√
2
)
2
+
(
7
√
2
)
2
=
196
=
14
2
(OK)
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
Neither
Step-by-step explanation:
5 x -10 = -50
4 x 9 = 36
-50 + 36 = -14 and therefore can not be orthogonal
sqrt(25+16)=sqrt(41)
sqrt(100+81)=sqrt(181)
sqrt(41) x sqrt(181) is not equal to -14 so therefore it is not parallel
So the answer is then neither
Answer:
61/5= 12.2 centimeters per minute
Step-by-step explanation:
Answer:
60%
Step-by-step explanation:
yiu take 100%-40%= 60%
