Answer:
Distribute, then combine like terms, subtract 10 from both sides of the equation, simplify, divide both sides of the equation by the same term, and simplify to get your solution.
Step-by-step explanation:
1.) Distribute
6−2(4−5)=40
6−8+10=40
2.) Combine like terms
6a-8a+10=40
-2a+10=40
3.) Subtract 10 from both sides of the equation
-2a+10=40
-2a+10-10=40-10
4.) Simplify
subtract the numbers
-2a+10-10=40-10
-2a=40-10
subtract the numbers
-2a=40-10
-2a=30
-2a=30
5.) Divide both sides of the equation by the same term
-2a=30
6.) Simplify
cancel terms that are in both the numerator or denominator
a=
Divide the numbers
a=
a=-15
a=-15
7.) Solution
a=-15
Answer:
it is given
, angle 2
, angle 3
, converse alternate exterior angles theorem
Step-by-step explanation:
We know that angle 1 is congruent to angle 3 and that line l is parallel to line m because it is <u>given
</u>. We see that <u>
angle 2
</u> is congruent to <u>angle 3</u> by the alternate interior angles theorem. Therefore, angle 1 is congruent to angle 2 by the transitive property. So, we can conclude that lines p and q are parallel by the <u>
converse alternate exterior angles theorem
</u>.