The flight is in the shape of a parabola with a vertex 5 feet above the water and 1/2 * 33 = 16.5 feet horizontally from the point of leaving the water
y = a(x - h)^2 + k
where (h,k) is the vertex of the parabola and here it is (5 , 16.5), so we have the function:-
y = a(x - 16.5)^2 + 5
when x = 0 y = 0 so
0 = a(-16.5)^2 + 5
which gives a = -0.018365
So our function for the flight path is
y = -0.018365(x - 16.5)^2 + 5 Answer
Given:
The graph of a line segment.
The line segment AB translated by the following rule:
To find:
The coordinates of the end points of the line segment A'B'.
Solution:
From the given figure, it is clear that the end points of the line segment AB are A(-2,-3) and B(4,-1).
We have,
Using this rule, we get
Similarly,
Therefore, the endpoint of the line segment A'B' are A'(2,-6) and B'(8,-4).
(3m^2-p)(3m-p^2)
You factor out the 3m^2 and p from the combined like terms and then group those into a factor and group the two identical factors together and (3m^2-p)(3m-p^2) is your answer.
You can but it isnt really a good idea to do that if you want full credit