When the Pka for formic acid = 3.77
and Pka = -㏒ Ka
3.77 = -㏒ Ka
∴Ka = 1.7x10^-4

when Ka = [H+][HCOO-}/[HCOOH]

when we have Ka = 1.7x10^-4 &[HCOOH] = 0.21 m
so by substitution: by using ICE table value
1.7x10^-4 = X*X / (0.21-X)
(1.7x10^-4)*(0.21-X) = X^2 by solving this equation for X

∴X = 0.0059
∴[H+] = 0.0059
∴PH= -㏒ [H+]
= -㏒ 0.0059
= 2.23

3 0

2 years ago

What group of substances does this substance belong to?

HACTEHA [7]

In comparison see it is very easy in goolge

4 0

2 years ago

Can someone please help and list what each type of thing they are? (Element, Compound, Mixture of elements, Mixture of compounds

enot [183]

1. B
2. C
3. E
4. D
5. A
6. B
7. A
8. E
9. A

Hope this helps!

5 0

2 years ago

2. Incoming wastewater, with BOD5 equal to 200 mg/L, is treated in a well-run secondary treatment plant that removes 90 percent

Lesechka [4]

Answer:

10.8 ml

Explanation:

The BOD is an empirical test to determine the molecular oxygen used during a specified incubation period (usually five days), for the biochemical degradation of organic matter (carbonaceous demand) and the oxygen used to oxidise inorganic matter.

See attached file

5 0

2 years ago