All categories

2 years ago

What is a quantum field?

2 answers:

8 0

It is the mathematical and conceptual framework for contemporary Elementary practical physicas. if that make sense to you.

nataly862011 [7]2 years ago

4 0

It is the theoretical framework for making models of subatomic particles.
An example you could look at for a model is a Feynman diagram.

Hope this helps :)

You might be interested in

If the average distance between bumps on a road is about 10 m and the natural frequency of the suspension system in the car is a

Mnenie [13.5K]

When you hit a bump every 0.9 seconds.

3 0

2 years ago

At a baseball game, you are in the cheap seats and far from the batter. You see the ball moving before you hear the sound of the

bogdanovich [222]

Answer:

it is he sound of source it uses ur ears to hear something unectpected can u give me brainly plz

Explanation:

6 0

2 years ago

What will be the change in velocity of a 850kg car if a force of 50,000 N

yKpoI14uk [10]

Answer:

29.412m/s

Explanation:

$F=ma$ where F= force, m= mass, and a=acceleration

we also know that,

a = Δv / t where Δv = change in velocity and t = time

thus F = m ( Δv / t)

$50000=850(\frac{v}{0.5})$

$\frac{50000}{1700}=$ Δv

29.412m/s=Δv

8 0

2 years ago

A 22.0 kg bucket of concrete is connected over a very light frictionless pulley to a 375 N box on the roof of a building as show

Veronika [31]

Answer:

vf = 3.27[m/s]

Explanation:

In order to solve this problem we must analyze each body individually and find the respective equations. The free body diagram of each body (box and bucket) should be made, in the attached image we can see the free body diagrams and the respective equations.

With the first free body diagram, we determine that the tension T should be equal to the product of the mass of the box by the acceleration of this.

With the second free body diagram we determine another equation that relates the tension to the acceleration of the bucket and the mass of the bucket.

Then we equalize the two stress equations and we can clear the acceleration.

a = 3.58 [m/s^2]

As we know that the bucket descends 1.5 [m], this same distance is traveled by the box, as they are connected by the same rope.

$x = \frac{1}{2} *a*t^{2}\\1.5 = \frac{1}{2}*(3.58) *t^{2} \\t = 0.91 [s]$

And the speed can be calculated as follows:

$v_{f}=v_{o}+a*t\\v_{f}=0+(3.58*0.915)\\v_{f}= 3.27[m/s]$

7 0

2 years ago

You are traveling on an airplane. The velocity of the plane with respect to the air is 110.0 m/s due east. The velocity of the a

Mice21 [21]

1. Vpa = 180m/s. @ 0 deg.
Vag = 40m/s @ 120 deg,CCW.

 Vpg = Vpa + Vag,
Vpg = (180 + 40cos120) + i40sin120,
Vpg = 160 + i34.64,
Vpg=sqrt((160)^2 + (34.64)^2)=163.7m/s.

2. tanA = Y / X = 34.64 / 160 = 0.2165,
A = 12.2 deg,CCW. = 12.2deg. North of East. 

3. 1 hr = 3600s. d = Vt = 163.7m/s * 3600s = 589,320m.

hope this helps

8 0

2 years ago