If y = cos(kt), then its first two derivatives are
y' = -k sin(kt)
y'' = -k² cos(kt)
Substituting y and y'' into 49y'' = -16y gives
-49k² cos(kt) = -15 cos(kt)
⇒ 49k² = 15
⇒ k² = 15/49
⇒ k = ±√15/7
Note that both values of k give the same solution y = cos(√15/7 t) since cosine is even.
Answer:
7*2=14 8x=8*8=64*2
Step-by-step explanation:
Thats how you basically do it now try it!
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Answer:
A triangle and a rectangle
Step-by-step explanation:
