2m⁴ - 18n⁶
2(m⁴) - 2(9n⁶)
2(m⁴ - 9n⁶)
2(m⁴ - 3m²n³ + 3m²n³ - 9n⁶)
2[m²(m²) - m²(3n³) + 3n³(m²) - 3n³(3n³)]
2[m²(m² - 3n³) + 3n³(m² - 3n³)]
2(m² + 3n³)(m² - 3n³)
Answer:
Both the boats will closet together at 2:21:36 pm.
Step-by-step explanation:
Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).
Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),
Formula : d=v*t
at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)
the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)
Formula : D=
⇒
Now let
∵
⇒ t= 450/1250
⇒ t= .36 hours
⇒ = 21 min 36 sec
Since F"(t)=0,
∴ This time gives us a minimum.
Thus, The two boats will closet together at 2:21:36 pm.
First calculate the circumference. Usually this is the diameter times pi, but since we are told to estimate pi, the circumference equals 56 * 22/7 or 176 feet.
In 4 minutes, 4 * 60 = 240 seconds pass. In this time, a 20 second period will occur 240/20 = 12 times.
So we know that the rider rotates 12 times and each rotation takes them 176 feet, meaning that they will travel 12 * 176 = 2112 feet
Answer:
See below
Step-by-step explanation:
Domain: set of x values
Range: set of y values
Function: no two x values are the same
Line 1:
Domain: {3, 4, 5}
Range: {1, 2, 3, 4}
Function: no since there are two points with x-coordinate 3
Line 2:
Domain: {-1, -2, 1, 2}
Range: {1, 3}
Function: yes since all x-coordinates are different
Line 3:
Domain: {-2, -1, 0, 1, 2}
Range: {0, 1, 4}
Function: yes since all x-coordinates are different