Answer:
The 95% confidence interval for the true average number of homes that a person owns in his or her lifetime is (4,6.2).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So
df = 50 - 1 = 49
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.0096
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 5.1 - 1.1 = 4
The upper end of the interval is the sample mean added to M. So it is 5.1 + 1.1 = 6.2.
The 95% confidence interval for the true average number of homes that a person owns in his or her lifetime is (4,6.2).
<span> Just plug in the value of b=3 in 4b^4, then you solve it, and your answer is 324</span>
The correct answer is three.
Answer:
A. (2x-3)/2
Step-by-step explanation:
Performing the long division indicated by the perimeter expression, you find ...
perimeter = (2x -3) + (10x +6)/(x^2 +2x)
Comparing this to the formula for the perimeter ...
perimeter = 2W +2L
where L is said to be of the form (ax +b)/(x^2 +2x)
we can match terms in the perimeter expression to see that ...
2W = 2x -3
2L = (10x +6)/(x^2 +2x)
The problem doesn't ask for it, but we can see that (a, b) = (5, 3). We can also see that ...
W = (2x -3)/2 . . . . . . . matches choice A
X=8
y=6x-4
y=6(8)-4
y=48-4
y=44