Answer:
tan
2
(
x
)
sec
+
3
Step-by-step explanation:
∫ (sec x − tan x) dx
∫ sec x dx + ∫ -tan x dx
∫ (sec²x + sec x tan x) / (sec x + tan x) dx + ∫ (-sin x / cos x) dx
ln(sec x + tan x) + ln(cos x) + C
r(A + B) = rA + rB,. (4). (r + s)A = rA + sA,. (5) r(sA)=(rs)A;. (6). A(BC)=(AB)C,.
which number to solve, it kinda seem difficult