Answer:
ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.
Step-by-step explanation:
It is given that the triangle ABC is dilated to produce triangle A'B'C' with scale factor 3/4.
If a figure is dilated then preimage and image are similar.
If scale factor is between 0 to 1, then preimage is reduction of image.
If scale factor is more that 1, then preimage is enlargement of image.
If scale factor is 1, then preimage is congruent to the image.
We know that
So,
Therefore, the ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.
Answer: B
<u>Step-by-step explanation:</u>
x³ - 3x² + 16x - 48 = 0
→ x²(x - 3) + 16(x - 3) = 0
→ (x² + 16) (x - 3) = 0
→ (x² - (-16)) (x - 3) = 0
→ (x - 4i)(x + 4i)(x - 3) = 0
→ x - 4i = 0 x + 4i = 0 x - 3 = 0
→ x = 4i x = -4i x = 3
2 imaginary roots and 1 real root
Answer: -6 Your welcome
Step-by-step explanation: I just did it and got a 100
Answer:
Step-by-step explanation:
Total distance = 3 + 2.5 = 5.5mi/h
Total time = 0.75h + 2hr = 2. 75 hr
Average speed = 5.5 / 2.75 = 2
Notice the tickmark on the angles, those angles are equal to each other.
now, notice the angle at the very top, the large triangle is really sharing it with smaller-inscribed triangle, and therefore is equal on both triangles.
therefore, the larger triangle, is similar with smaller-inscribed triangle by AA.
what the dickens does that mean?