Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and 
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To find:
The 
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Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]
In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
The base angles of an isosceles triangle are congruent. So,
[Base angles of an isosceles triangle]
Using the angle sum property in triangle AOB, we get
Hence, the measure of angle AOB is 120 degrees.
Answer:
-7π/3 or -420 degrees
Step-by-step explanation:
So we know that the arrow has made one full rotation and that it is moving in a clockwise direction. So already we have -2π degrees.
The arrow stops at π/6 before the next π/2 rotation. Therefore we find the difference between the two.
π/2 - π/6
3π/6 - π/6 = 2π/6
π/3
Since this is still clockwise, we make this negative. So the measure of the angle shown by the arrow is -2π - π/3
Answer:
-2
Step-by-step explanation:
41 - 8m - 57 = 0
41- 8m = 57
-8m = 57-41
-8m = 16
m = -16/8
m = -2
The angles of a triangle add up to 180 degrees
65 + 3x - 10 + 2x = 180
5x + 55 = 180
5x = 180 - 55
5x = 125
x = 125/5
x = 25 <====
m < B = 3x - 10 = 3(25) - 10 = 75 - 10 = 65 <== B is 65 degrees
m < C = 2x......= 2(25) = 50 <== C is 50
Answer:
6cm is the missing length
Step-by-step explanation:
See the 10cm and the 4cm?
If you look at in a way if you added 6 more centimeters to the 4cm it would be 10, leaving 6cm as the missing length.
