For #10
x=2 w(x)= 5
x=0 w(x)=-9
x=1 w(x)=-1
x=4 w(x)=7
To get these answers, you must use the p(x) table. When x=2, p(x)=6. So you would substitute p(x) for 6 and solve. That would be what you would do for the rest of teh problems.
For #12, the answer would be 5x^2+15x+5
Just mutiply the areas of the out side and inside and subtract them
The gallons of the first brand of antifreeze should be 60 gallons.
The gallons of the second brand of antifreeze should be 90 gallons.
<h3>What are the linear equations that represent the question?</h3>
0.2f + 0.45s = 52.50 (0.35 x 150) equation 1
f + s = 150 equation 2
Where:
- f = gallons of the first antifreeze
- s = gallons of the second antifreeze
how many gallons of each brand of antifreeze must be used?
Multiply equation 2 by 0.2
0.2f + 0.2s = 30 equation 3
Subtract equation 3 from equation 2
0.25s = 22.50
s = 22.50 / 0.25
s = 90
f = 150 - 90 = 60 gallons
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Answer:
-151
Step-by-step explanation:
first find the value of g(6)
g(6) = -3 × 6 - 8 ➡-24
then put this value fir f(g(6))
f(-24) = 6 × -24 -7 ➡ -151
It would be the square root of 3
Answer:
It is 6.9
Step-by-step explanation:
6.85565
put
6.85
5 can be rounded up so
6.9 is answer