Question

If the moles and volume of a gas are held constant, dropping the temperature from 40 degrees Celsius to 20 degrees Celsius causes would cause an initial pressure of 3 atmospheres to drop to 1.5 atmospheres.
T/F

Answer 1

It would cause a drop but I am not sure  double check other answers 

Answer 2

Answer:

False.

Explanation:

Hello,

In this case, as the moles are held constant, one uses the Gay-Lussac's law in order to relate both the temperature and the pressure at the beginning and at the end of the experiment via the following relationship:

$P_1T_2=P_2T_1$

By solving for the pressure at the second (final) state we can substantiate whether the 1.5 atm are correct as shown below:

$P_2=\frac{P_1T_2}{T_1}=\frac{3atm*293.15K}{313.15K}= 2.8 atm$

Therefore, even when the pressure is correctly decreased, the given value is wrong as 2.8 atm is the correct final pressure, in this manner, the statement is false.

Best regards.