Answer:
2x - 4
Step-by-step explanation:
Answer:
Please where are the boxes
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
25 were on the roller coaster.
Multiplication and subtraction
Dy/dx=1/2, 1/2, 1/2 etc
So this is a linear equation of the form y=mx+b where m=dy/dx=1/2 so
y=x/2 +b, now we can use any point to solve for the y-intercept, "b", I'll use (7,0)
0=7/2 +b
b=-7/2 so
y=x/2-7/2
y=(x-7)/2