The handshake problem!
Each of the five will play against 4 others, but since A vs B can be considered the same game as B vs A, so there are 5*4/2=10 matches.
The answer is 6 pi because you have to divide 18 by 3. That gives you 6.
Answer:
1C=8Fl ( not how many are in 4 cups look in explanation)
Step-by-step explanation:
In 4 cups there 32FlOz. this is becuase you want to find how many floz are in 4 cups so you multiply the whole equation by 4. you get 4C = 32Fl or 4cups = 32 fluid ounces
You know that three points A,B,CA,B,C (two vectors A⃗ BA→B, A⃗ CA→C) form a plane. If you want to show the fourth one DD is on the same plane, you have to show that it forms, with any of the other point already belonging to the plane, a vector belonging to the plane (for instance A⃗ DA→D).
Since the cross product of two vectors is normal to the plane formed by the two vectors (A⃗ B×A⃗ CA→B×A→C is normal to the plane ABCABC), you just have to prove your last vector A⃗ DA→D is normal to this cross product, hence the triple product that should be equal to 00:
A⃗ D⋅(A⃗ B×AC)=0