A pyramid has a square base with sides of length s the height of The pyramid is equal to 1/2 Of the length of a side on the base
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Answer:
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Step-by-step explanation:
<em>Given: Side lengths of a right triangle 3,4 and 5 units. </em>
<em> To draw: A right triangle with the given side length. </em>
<em> Solution: </em>
<em> We know, in a right angle triangle hypotenuse is the longest side and satisfying Pythagoras theorem. </em>
<em> From the given side length, </em>
<em> Hypotenuse = 5 unit </em>
<em> We can take any of the base and perpendicular. </em>
<em> Let, Base = 3 unit </em>
<em> Perpendicular = 4 unit. </em>
<em> It a right-angle triangle with a hypotenuse 5 unit. </em>
<em> Now we draw a right angle triangle taking in the first 3 base and 4 perpendicular and second 3 perpendicular and 4 bases.</em>
