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2 years ago

Help me with 5 and 6 please I really don’t get it

Mathematics

1 answer:

alekssr [168]2 years ago

6 0

Answer:

5 is congruent, 6 is not congruent

Step-by-step explanation:

In 5, both shapes have the same side lengths. This means their areas are the same, making them congruent.

In 6, the shapes do not have the same side lengths. This means their areas are not the same, making them not congruent.

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8 0

2 years ago

Given that f(x) = 2x + 1 and g(x) = −5x + 2, solve for f(g(x)) when x = 3.

Anon25 [30]

The first step in solving for f(g(x)) when x=3, is solve for g(x). The answer of g(x) when x is equal to 3 is -(5) multiplied by 3 add by 2. Therefore, g(x) is -13. Then substitute the value of g(x) to f(x). The answer of f(-13) is 2 multiplied by -13, then add 1. So, the final answer is, f(x)=-25.

3 0

2 years ago

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ABCD is a rectangle with diagonals segment AC and segment BD. If AC = 2х + 10 and BD -=56, find the value of х." О23О33О 78 O 12

Aleks04 [339]

Answer:

Step-by-step explanation:

The diagonals of a rectangle are equal.

2x + 10 = 56 That minus sign can't be there. Subtract 10 from both sides.

2x = 56 - 10 Combine

2x = 46 Divide by 2

x = 46/2

x = 23

7 0

2 years ago

Please help. 10 points and brainliest.

Snezhnost [94]

Answer:

$\frac{a^2}{b^2}$

Step-by-step explanation:

Apply the exponent rule $a^b*a^c=a^b+c$ to a

$a^4*a^-^2=a^4^-^2=a^2$

$b^3a^2b^-^5$

Apply the exponent rule to b

$b^3*b^-^5=b^3^-^5=b^-^2$

Apply the exponent rule $a^-^b=\frac{1}{a^b}$

$b^-^2=\frac{1}{b^2}=\frac{1}{b^2}a^2=\frac{a^2}{b^2}$

6 0

2 years ago

Avaluate 2^3x-1 for x=1

DENIUS [597]

Answer:

4 or 7 (Check the explanation to see which one your equation actually is.

Step-by-step explanation:

One thing I want to clarify for you, It's Evaluate, not Avaluate.

Okay so, we want to find the value of 2^3x-1 and we know x = 1.

You didn't really clarify if the expression was $2^{3x-1}$ or $2^{3x}-1$ , so I'll be doing both:

For $2^{3x-1}$ , we should plug in x to get $2^{3(1)-1}$ and then simplify to get $2^{2}$ .

2 to the power of 2 or $2^{2}$ is equal to 2 * 2 or 4.

The second one, $2^{3x}-1$ , we should plug in x to get $2^{3(1)}-1$ and then to become $2^{3}-1$ . 2 to the power of 3 or $2^{3}$ is 8 and then minus 1 is 7.

7 0

2 years ago

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