How many of the numbers from 10 through 98 have the sum of their digits equal to a perfect square?
1 answer:
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It's evident that the first four terms are 4, 4/3, 4/9, and 4/27. So the fourth partial sum of the series is
It's as easy as adding up the fractions, but I bet this is supposed to be an exercise in taking advantage of the fact that the series is geometric and use the well-known formula for computing such a sum.
Multiply the sum by 1/3 and you have
Now subtracting this from
gives
That is, all the matching terms will cancel. Now solving for, you
have
It's as easy as adding up the fractions, but I bet this is supposed to be an exercise in taking advantage of the fact that the series is geometric and use the well-known formula for computing such a sum.
Multiply the sum by 1/3 and you have
Now subtracting this from
That is, all the matching terms will cancel. Now solving for
have