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2 years ago

How does increasing the amount of charge on an object affect the electric force it exerts on another charged object?

Physics

1 answer:

gregori [183]2 years ago

4 0

Hi Mandy!

Question - How does increasing the amount of charge on an object affect the electric force it exerts on another charged object?

Answer - The electric force increases because the amount of charge has a direct relationship to the force.

Why - The affect that the force exerts on another object that is also charge is becase the fact that when the electric force increases is when the charge is direct with the object with the force.

Hope This Helps :)

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Which is occurring when work is being done?

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Answer:

When work is being done, the practie of labor is being performed. When work isn't being completed, this is a sign of procrastination.

Explanation:

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Why is it important to be able to trace the pole connection on a meter back to the same type of pole at the electrical source?

lozanna [386]

Answer:

Explanation:

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2 years ago

the maximum intensity levels of a trumpet, trombone, and a bass drum, each at a distance of 3m are 94 dB, 107dB, and 113dB respe

Gwar [14]

Answer:

β = 114 db

Explanation:

The intensity of sound in decibles is

β = 10 log $\frac{I}{I_{o}}$

in most cases Io is the hearing threshold 1 10-12 W / cm²

let's calculate the intensity of each instrument

I / I₀ = 10 (β / 10)

I = I₀ 10 (β / 10)

trumpet

I1 = 1 10⁻¹² 10 (94/10)

I1 = 2.51 10⁻³ / cm²

Thrombus

I2 = 1 10⁻¹² 10 (107/10)

I2 = 5.01 10-2 W / cm²

low

I3 =1 1-12 (113/10) W/cm²

I3 = 1,995 10-1 W / cm²

when we place the three instruments together their sounds reinforce

I_total = I₁ + I₂ + I₃

I_ttoal = 2.51 10-3 + 5.01 10-2 + 1.995 10-1

I_total = 0.00251 + 0.0501 + 0.1995

I_total = 0.25211 W / cm²

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7 0

2 years ago

In a football game, the running back takes a handoff and begins running toward midfield at 3.21 yards/s . As he moves through hi

Inessa [10]

Given Information:

Initial speed = u = 3.21 yards/s

Acceleration = α = 1.71 yards/s²

Final speed = v = 7.54 yards/s

Required Information:

Distance = s = ?

Answer:

Distance = s = 13.61

Explanation:

We are given the speeds and acceleration of the runner and we want to find out how much distance he covered before being tackled.

We know from the equations of motion,

v² = u² + 2αs

Where u is the initial speed of the runner, v is the final speed of the runner, α is the acceleration of the runner and s is the distance traveled by the runner.

Re-arranging the above equation for distance yields,

2αs = v² - u²

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Therefore, the runner traveled a distance of 13.61 yards before being tackled.

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2 years ago

The compressor on an air conditioner draws 66.1 a when it starts up. the start-up time is about 0.388 s. how much charge passes

Ierofanga [76]

The current intensity is defined as the amount of charge flowing through a certain point of a wire divided by the time interval:
$I= \frac{Q}{\Delta t}$
where Q is the charge and $\Delta t$ is the time. Re-arranging the formula, we have
$Q=I \Delta t$

for the compressor in our problem, the intensity of current is I=66.1 A, while the time is $\Delta t= 0.388 s$ , so the amount of charge that crosses a certain point of the circuit during this time is
$Q=I \Delta t=(66.1 A)(0.388 s)=25.65 C$

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2 years ago