Answer:
3. 4x^2y
Step-by-step explanation:
The GCF of 36 and 14 is 4.
The GCF of x^2y and x^2y^2 is x^2y
Multiply the two GCF and you get 4x^2y
Answer:
3.9 mi/h
Step-by-step explanation:
If the boy is rowing perpendicular to the current, the two vectors form a right triangle.
AB represents the downstream current, BC is the speed across the river, and AC is the ground speed of the boat
AC^2 = 2.4^2 + 3.1^2 =5.76 + 9.61 = 15.37
AC = sqrt(15.37) = 3.9 mi/h
The boat's speed over the ground is 3.9 mi/h.
I think the answer to 14 is J
Step-by-step explanation:
(-7)+(-6)+(-1)=-14
(-14)-3=-11
-11÷7=-1.5714285714286 or -2 if you round too the tenths place
Remark
I don't know exactly what level you are in, but the obvious factors are
y = 2x*(x^3 + 11x + 30)
This gives one more factor somewhere around x = -11.3 . Notice that the minimum is around - 3000 or so. I don't think anyone is going to try and take this any further. My calculator figures out cubics and gives an answer of -11.23. There are two other roots but they are a complex pair.
Answer
factor 1: 2x
factor 2: x^3 + 11x^2 + 30