We model the ticket as a rectangle. For this case what you should know is that the perimeter of the rectangle is given by: P = 2w + 2l The area of the rectangle is given by: A = w * l In both cases: w: width l: long We have the following system of equations: 32 = 2w + 2l 60 = w * l Solving the system we obtain: The dimensions of the ticket are: (10 cm) * (6 cm) Answer: the dimensions of the ticket are: (10 cm) * (6 cm) Note: see attached image for system solution