A water trough is 7 m long and has a cross-section in the shape of an isosceles trapezoid that is 30 cm wide at the bottom, 70 c m wide at the top, and has height 40 cm. If the trough is being filled with water at the rate of 0.2 m3/min how fast is the water level rising when the water is 20 cm deep
2 answers:
Step-by-step explanation:
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Answer:
The degree of fastness by which the water is rising is 210 seconds
Step-by-step explanation:
The volume of the trough when the water depth is 20 cm is first calculated
Volume of the trough (Trapezoidal Prism) = LH (A + B) × 0.5
Where L is the length of the trough, H is the height of the trough and A and B are parallel width of the top and bottom of the trough
Volume of the trough = 7 × 0.2 (0.3 + 0.7) × 0.5 = 0.7m³
The fastness at which the water is rising is = Volume ÷ water flow rate = 0.7 ÷ 0.2 = 3.5 min = 210 seconds
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Answer:
7:5
Step-by-step explanation:
49/7 = 7 and 35/7 = 5
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Sorry idk, but I’ll try to do it
You divide -15 on both sides to keep the x alone
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