two ropes, ad and bd, are tied to a peg on the ground at point d. the other ends of the rope are tied to points, a and b, on a f
lagpole. angle adc measure 45 degrees and angle bdc measures 30 degrees. IF the distance between point d and the flagpole is 5*the square root of 3 what is the distance between points a and b on the flagpole?
I guess C is the point where the flagpole touches the ground. If so:
ADC is a an isosceles right triangle. (ACD = 90, ADC = 45, then DAC=45). So DC = AC = 5√3. Now let's consider the right triangle BCD: ADC = 30, tan 30 = BC/DC: tan 30 = BC/5√3, or tan30 = √3/3 → √3/3 = BC/5√3 and BC =5. But AB = AC - BC AB = 5√3 - 5 AB =5(√3 - 1) or AB = 3.66
