B because distributive property goes like this:
a(b+c)
a(b)+a(c)
That's just an example though
Answer:
(D)
Step-by-step explanation:
From the figure, we have
The coordinates of the point F are: (-4,1).
The coordinates of the point G are: (0,-2)
The coordinates of the point J are: (0,4) and
The coordinates of the point H are: (-4,-2).
Now, the slope of the line FG is :
And, the slope of the line HJ is:
Now, 
which is not possible, thus They are not perpendicular because their slopes are not negative reciprocals.
I'm only going to alter the left hand side. The right side will stay the same the entire time
I'll use the identity tan(x) = sin(x)/cos(x) and cot(x) = cos(x)/sin(x)
I'll also use sin(x+y) = sin(x)cos(y)+cos(x)sin(y) and cos(x+y) = cos(x)cos(y)-sin(x)sin(y)
So with that in mind, this is how the steps would look:
tan(x+pi/2) = -cot x
sin(x+pi/2)/cos(x+pi/2) = -cot x
(sin(x)cos(pi/2)+cos(x)sin(pi/2))/(cos(x)cos(pi/2)-sin(x)sin(pi/2)) = -cot x
(sin(x)*0+cos(x)*1)/(cos(x)*0-sin(x)*1) = -cot x
(0+cos(x))/(-sin(x)-0) = -cot x
(cos(x))/(-sin(x)) = -cot x
-cot x = -cot x
Identity is confirmed
To find T, you add 25 to both sides, isolating the varible. This gives you T=-19
Hope this helped!
Answer:
a+b
Step-by-step explanation:
=1a+1b
=1(a+b)
=a+b
