Use the information in the tables to determine whether the solution of the salt formed from the given acid + base combinations w
ill be acidic, basic, or neutral.
HCl + NaOH:
HCl + NH4OH:
CH3COOH + KOH:
HCl + NaOH:
HCl + NH4OH:
CH3COOH + KOH:
2 answers:
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Answer:
0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.
Explanation:
Mass percentage of oxalic acid = 5.50%
This means that in 100 grams of solution there are 5.50 grams of oxalic acid.
Mass of solution , m = 100
Volume of the solution = V
Density of the solution = d = 1.024 g/mL
V = 97.66 mL = 0.09766 L
(1 mL = 0.001 L)
Moles of oxalic acid =
The molarity of the solution :
0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.