Answer:
B. AA
Step-by-step explanation:
The diagram given shows that two angles in ∆ABC are congruent to two corresponding angles in ∆STU.
Invariably, the third unknown angle of both triangles would also be equal going by the third angle theorem.
Thus, based on the AA Similarity Theorem which says that two triangles are similar to each other if two corresponding angles of one is congruent to two angles in the other, ∆ABC ~ ∆STU.
<em><u>Answer</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em><em><u> </u></em><em><u>opti</u></em><em><u>on</u></em><em><u> </u></em><em><u>3</u></em><em><u>r</u></em><em><u>d</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em><em><u> </u></em>
Step-by-step explanation:
∆FGE ~ ∆ JKL
i.e, Angle FGE = angle JKL = 63°
and angle GEF = angle KLJ = 29°
also, angle GFE = angle KJL = 88°
so, the ∆FGE ~ ∆ JKL by AA property of similarity !!
• not other options because if we take corresponding angle they are not equal
For eg. for ∆ EFG ~ ∆ JKL
the angle EFG must be equal to angle JKL to be similar !!
but they are not equal !!
so, they are not similar !!
and such ,all other options except 3rd is wrong !!
.484 is the ansewer since 4.4 *.11 is .484 hope this helps
When the car is moving, it has Kinetic Energy. As soon as the car entercount with the spring, its Kinetic Energy will transfer to Elastic Potential Energy.
<span>KE = EPE </span>
<span>1/2mv^2 = 1/2kx^2 </span>
<span>change the speed into m/s </span>
<span>50 km/hr = 13.9 m/s </span>
<span>1/2(1200)(13.9)^2 = 1/2k(2.2)^2 </span>
<span>now you do the math to solve for k.
k= 115926/2.42
K= 47903.30</span>