By definition, electromagnetic induction is the term that is generally used to describe the method of generating a potential difference across a conductor through a changing magnetic field. In addition, the induce current would be minimised if the loop is placed parallel to the magnetic field itself. Therefore, C.
1. Multiply: (3x+1)(x+2) Answer:3x^2+7x+2
2.Remember to combine all like terms, and FOIL to check if you had factored a trinomial correctly.
Answer:
what is the rest of your question haha
Step-by-step explanation:
The factored form of the given expressions are
y = (x -2)(x +7)
y = (x +6)(x -9)
y = (x +2)(x +6)
y = (x -5)(x -6)
y = (x +5)(x -5)
y = (x -1)(x +9)
y = (x +4)(x -4)
<h3>Factoring quadratic expressions</h3>
From the question we are to factor the given quadratic expressions
y = x² +7x -2x - 14
y = x(x +7) -2(x +7)
y = (x -2)(x +7)
y = x² -9x +6x - 54
y = x(x -9) +6(x -9)
y = (x +6)(x -9)
y = x² +6x +2x +12
y = x(x +6) +2(x +6)
y = (x +2)(x +6)
y = x² -6x -5x +30
y = x(x -6) -5(x -6)
y = (x -5)(x -6)
y = (x +5)(x -5)
y = x² +9x -x -9
y = x(x +9) -1(x +9)
y = (x -1)(x +9)
y = (x +4)(x -4)
Hence, the factored form of the given expressions are
y = (x -2)(x +7)
y = (x +6)(x -9)
y = (x +2)(x +6)
y = (x -5)(x -6)
y = (x +5)(x -5)
y = (x -1)(x +9)
y = (x +4)(x -4)
Learn more on Factoring quadratic expressions here: brainly.com/question/52959
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F(q)=0
so, q^2 - 125 = 0
(q)^2 - (5)^2 = 0
(q+5) (q-5) = 0
q = 5, -5